Router timed shutdown device DIY

Source:Site sorting Author:Rank nameDecember 31, 2011 11:39
0
[guide]When the router timed shutdown device is powered on, the + 5.5V power supply charges C1 through R1 and C2 through R2, but due to the large time constants of R1 and C1 So charge C2 first.
key word:Timed shutdownRouter

The circuit is shown in the attached figure (click to enlarge) When powered on, the + 5.5V power supply charges C1 through R1 and C2 through R2, but due to the large time constants of R1 and C1 So charge C2 first. Since the voltage of the ② pin of 555 is higher than that of the ⑥ and ⑦ pins, its ③ pin will output low level, resulting in Q1 cut-off, Q2 conduction, relay J pull in, contact J1 disconnect and 220V output cut off. The voltage on C1 will rise slowly due to charging After about 1.5 hours, the voltage of pins ⑥ and ⑦ is higher than that of pin ②. 555 turns over immediately, and the output of pin ③ becomes high level, resulting in Q1 conduction, Q2 cut-off, relay J release and J1 close. Then there is 220V output, and the router and cat are powered on and work. In other words, the equipment can work normally only after it is powered on for about 1.5 hours.

To speed up the first boot time Button switch K1 is set in the circuit Its function is to accelerate the charging process of C1 This causes Q2 to cut off quickly, relay J releases and J1 closes Make the router and cat work quickly. In case of power failure, you can also press K1 to start up quickly.

Set the alarm clock to 4:00 in the middle of the night At that time, the alarm clock rings and the audio output of the bell is AC It is rectified into DC positive voltage through D1 and added to Q3 base to make it conductive, so its collector voltage decreases, which makes the voltage of the ② pin of 555 lower than the ⑥ and ⑦ pins, 555 immediately turns over, and the output of the ③ pin becomes low level again, resulting in Q1 cut-off, Q2 conduction, relay J pull in, J1 disconnect, 220V has no output, and the router and cat immediately lose power and rest. Because of charging, the voltage on C1 will slowly rise up after 1.5 hours Repeat the cycle again.

In other words, as long as the ② pin of 555 is not triggered, Q2 will remain cut-off and the relay will not be pulled in. 220V will always have output The router and cat will continue to work. So the function of the digital clock is to let the router and the cat rest for about 1.5 hours every day. 555 is only a delay device, because the alarm clock can only go off for one minute Less than 1.5 hours. The delay length of 555 is about 1.1 times r1c1, i.e. 1.1 & times; 10MΩ&TImes; four hundred and seventy μ F = 5170 seconds (about 1.44 hours). In fact, it is best to delay to 3 hours, but the electrolytic capacitor C1 should be increased to 1000 μ F. As a result, leakage will also increase and the circuit will be unstable.

The digital clock (or digital meter) is powered by floating charge method. The charging current flows through the LED, so it is always on Therefore, it can also be used as indicator light and lighting lamp. Transformer T1 adopts 12V / 1W. In order to save power, a 0.15 capacitor is specially connected in series. Because the relay wire package is 6V / 60mA, in fact, the 5.5V power supply can work reliably. A silicon diode is connected in series on the voltage stabilizing integrated block 7805 Its output becomes 5.5V, which can save a little electricity. R3, C3 and C2 in the figure can resist interference and filter the alarm signal. The relay is designed to use normally closed contacts to connect the router and cat, so its cable package is not energized for 22.5 hours a day It saves power for the device.

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    ,

    The circuit is shown in the attached figure (click to enlarge) When powered on, the + 5.5V power supply charges C1 through R1 and C2 through R2, but due to the large time constants of R1 and C1 So charge C2 first. Since the voltage of the ② pin of 555 is higher than that of the ⑥ and ⑦ pins, its ③ pin will output low level, resulting in Q1 cut-off, Q2 conduction, relay J pull in, contact J1 disconnect and 220V output cut off. The voltage on C1 will rise slowly due to charging After about 1.5 hours, the voltage of pins ⑥ and ⑦ is higher than that of pin ②. 555 turns over immediately, and the output of pin ③ becomes high level, resulting in Q1 conduction, Q2 cut-off, relay J release and J1 close. Then there is 220V output, and the router and cat are powered on and work. In other words, the equipment can work normally only after it is powered on for about 1.5 hours.

    To speed up the first boot time Button switch K1 is set in the circuit Its function is to accelerate the charging process of C1 This causes Q2 to cut off quickly, relay J releases and J1 closes Make the router and cat work quickly. In case of power failure, you can also press K1 to start up quickly.

    Set the alarm clock to 4:00 in the middle of the night At that time, the alarm clock rings and the audio output of the bell is AC It is rectified into DC positive voltage through D1 and added to Q3 base to make it conductive, so its collector voltage decreases, which makes the voltage of the ② pin of 555 lower than the ⑥ and ⑦ pins, 555 immediately turns over, and the output of the ③ pin becomes low level again, resulting in Q1 cut-off, Q2 conduction, relay J pull in, J1 disconnect, 220V has no output, and the router and cat immediately lose power and rest. Because of charging, the voltage on C1 will slowly rise up after 1.5 hours Repeat the cycle again.

    In other words, as long as the ② pin of 555 is not triggered, Q2 will remain cut-off and the relay will not be pulled in. 220V will always have output The router and cat will continue to work. So the function of the digital clock is to let the router and the cat rest for about 1.5 hours every day. 555 is only a delay device, because the alarm clock can only go off for one minute Less than 1.5 hours. The delay length of 555 is about 1.1 times r1c1, i.e. 1.1 & times; 10MΩ&TImes; four hundred and seventy μ F = 5170 seconds (about 1.44 hours). In fact, it is best to delay to 3 hours, but the electrolytic capacitor C1 should be increased to 1000 μ F. As a result, leakage will also increase and the circuit will be unstable.

    The digital clock (or digital meter) is powered by floating charge method. The charging current flows through the LED, so it is always on Therefore, it can also be used as indicator light and lighting lamp. Transformer T1 adopts 12V / 1W. In order to save power, a 0.15 capacitor is specially connected in series. Because the relay wire package is 6V / 60mA, in fact, the 5.5V power supply can work reliably. A silicon diode is connected in series on the voltage stabilizing integrated block 7805 Its output becomes 5.5V, which can save a little electricity. R3, C3 and C2 in the figure can resist interference and filter the alarm signal. The relay is designed to use normally closed contacts to connect the router and cat, so its cable package is not energized for 22.5 hours a day It saves power for the device.

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